2011 Canadian Computing Competition, Stage 1

Problem J2: Who Has Seen The Wind

Margaret has looked at the wind floating over the prairies for a long time. After these observations, she has created a formula that will describe the altitude of a weather balloon launched from her house. In particular, her equation predicts the altitude A (in metres above the ground) at hour t after launching her balloon is:

$A = -6t^4 + ht^3 + 2t^2 + t$

where h is an integer value representing the humidity as a value between 0 and 100 inclusive.

Margaret is curious at what the earliest hour is (if any) that her weather balloon will hit the ground after launch, so long as it is no more than the maximum time, M, that Margaret is willing to wait. You can assume that the weather balloon touches ground when A ≤ 0.

Input Format

The input is two non-negative integers: h (0 ≤ h ≤ 100), the humidity factor, followed by M (0 < M < 240), the maximum number of hours Margaret will wait for the weather balloon to return to ground.

Output Format

The output will be one of the following possibilities:

  • The balloon does not touch ground in the given time.
  • The balloon first touches ground at hour:
    T

where T is a positive integer value representing the earliest hour when the balloon has altitude less than or equal to zero.

Sample Cases

Input

30
10

Output

The balloon first touches ground at hour:
6

Input

70
10

Output

The balloon does not touch ground in the given time.

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Best Solutions


Point Value: 5
Time Limit: 2.00s
Memory Limit: 16M
Added: Mar 01, 2011

Languages Allowed:
C++03, PAS, C, HASK, ASM, RUBY, PYTH2, JAVA, PHP, SCM, CAML, PERL, C#, C++11, PYTH3

Comments (Search)

magicalsoup on Jan 23, 2018 - 3:34:15 am UTC quadratic
  • (2/0)
so bascially its asking us do to quadratics