PEG-O-Stripes
Mo has been attending every single PEG practice lately (so now we know which Mo we are talking about) and he got a little bit—hmmm—bored. To bring some excitement, he invented a new game: PEG-O-STRIPES, and decided to challenge another Mo to a duel. However, he wants to win for sure, so he hired David (Pritchard, of course) to come up with a winning strategy for him, or at least to tell him whether he can win. Dave agreed under the condition that Mo (A.) will always begin.
PEG-O-STRIPES involves two players who are given an infinite supply of stripes in three colours: red, green and blue. All of the red stripes have dimensions R×1, blue ones: B×1, and green ones: G×1, where R, B, and G are given natural numbers. Players take turns by placing given stripes on a board with dimensions L×1. They have to follow the following rules:
- stripes can be placed anywhere within the board
- stripes cannot overlap
The first player who cannot place any stripes on the board according to the given rules loses. The player that begins is said to have a winning strategy, if he wins no matter how the second player plays. Write a program that can determine whether the first player has a winning strategy for given dimensions L, R, B, and G. If yes, output 1, if no, output 2.
Input
One line containing three numbers: R, B, and G (1 < R, B, G ≤ 1000).
One line containing M (1 < M ≤ 1000): a number of boards to consider.
M lines each containing the length L (1 < L ≤ 1000) of a board to be considered.
Output
For each test case, output 1 if the first player has a winning strategy, and 2 if not.
Separate test cases by a blank line.
Sample Input
1 5 1 4 1 5 6 999
Sample Output
1 1 2 1
All Submissions
Best Solutions
Point Value: 15
Time Limit: 2.00s
Memory Limit: 16M
Added: Feb 24, 2009
Languages Allowed:
C++03, PAS, C, HASK, ASM, RUBY, PYTH2, JAVA, PHP, SCM, CAML, PERL, C#, C++11, PYTH3
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