COCI 2007/2008, Contest #5

Task PASCAL

Little Frane is already in tenth grade, but is still struggling with Pascal in computer class. For homework, his teacher wrote the following program into his notebook, and he needs to determine the output, given the integer N.

    readln(N);
    counter := 0;
    for i := N-1 downto 1 do begin
        counter := counter + 1;
        if N mod i = 0 then break;
    end;
    writeln(counter);

Write a program which solves Frane's problem.

Input

The first line of input contains the integer N (1 ≤ N ≤ 10⁹).

Output

Output the result on a single line.

Examples

1

0

10

5

27

18

All Submissions
Best Solutions

Point Value: 5
Time Limit: 1.00s
Memory Limit: 32M
Added: Jan 29, 2009

Languages Allowed:
C++03, PAS, C, HASK, ASM, RUBY, PYTH2, JAVA, PHP, SCM, CAML, PERL, C#, C++11, PYTH3

Comments (Search)

It’s too slow, duh! And the code provided from this question is too slow, you should  understand this question before just asking why your code does not work

If you don't have an understanding of Pascal, how would you do this?
I think I understand, but what about the rest?

The good thing is that this reads very easily as near-direct English.

Here are equivalents in C++ and Python.
[code]
// C++
int N;
cin >> N;
int counter = 0;
for (int i = N - 1; i >= 1; i--) {
    counter = counter + 1;
    if (N % i == 0) break;
}
cout << counter << '\n';

# Python
N = int(input())
counter = 0
for i in range(N - 1, 0, -1):
    counter = counter + 1
    if N % i == 0: break
print(counter)
[/code]

 
// C++ 
int N; 
cin >> N; 
int counter = 0; 
for (int i = N - 1; i >= 1; i--) { 
    counter = counter + 1; 
    if (N % i == 0) break; 
} 
cout << counter << '\n'; 
 
# Python 
N = int(input()) 
counter = 0 
for i in range(N - 1, 0, -1): 
    counter = counter + 1 
    if N % i == 0: break 
print(counter) 

Can I get a Java equivalent?

It's equivalent to the C++ code, except of course that it handles i/o differently.