1996 Canadian Computing Competition, Stage 2
Day 1, Problem 2: Safebreaker
We are observing someone playing a game similar to Mastermind™. The object of this game is to find a secret code by intelligent guesswork, assisted by some clues. In this case the secret code is a 4-digit number in the inclusive range from 0000 to 9999, say "3321". The player makes a first random guess, say "1223" and then, as for each of the future guesses, gets a clue telling how close the guess is. A clue consists of two numbers: the number of correct digits (in this case, one: the "2" at the third position) and the additional number of digits guessed correctly but in the wrong place (in this case, two: the "1" and the "3"). The clue would in this case be: "1/2". For the guess "1110", the clue would be "0/1", since there are no correct digits and only one misplaced digit. (Notice that there is only one digit 1 misplaced.)
Write a program that, given a set of guesses and corresponding clues, tries to find the secret code.
The first line of input specifies the number of test cases (N) your program has to process. Each test case consists of a first line containing the number of guesses G (0 ≤ G ≤ 10), and G subsequent lines consisting of exactly 8 characters: a code of four digits, a blank, a digit indicating the number of correct digits, a "/", and a digit indicating the number of correct but misplaced digits.
For each test case, the output contains a single line saying either:
impossible if there is no code consistent with all guesses.
n , where n is the secret code, if there is exactly one code consistent with all guesses.
indeterminate if there is more than one code which is consistent with all guesses.
4 6 9793 0/1 2384 0/2 6264 0/1 3383 1/0 2795 0/0 0218 1/0 1 1234 4/0 1 1234 2/2 2 6428 3/0 1357 3/0
3411 1234 indeterminate impossible
Point Value: 10
Time Limit: 2.00s
Memory Limit: 16M
Added: Jun 24, 2013
C++03, PAS, C, HASK, ASM, RUBY, PYTH2, JAVA, PHP, SCM, CAML, PERL, C#, C++11, PYTH3
The two digits in the wrong place are the "1" and the "3", not "1" and "2".