University of Toronto ACM-ICPC Tryouts 2012

B: Attack of the Bloons

The Bloons (not to be confused with balloons) are attacking! They are attempting to navigate your course of L (1 ≤ L ≤ 1000) cells, laid out in a row and numbered from 1 to L. You don't know what they'll do to you if they manage reach the end, and you don't want to find out! To that end, you've constructed some defensive towers along the course. You might say that this is a Bloons Tower Defense.

There are N (1 ≤ N ≤ 1000) towers ready to take out any Bloons that get close. The i-th tower is located next to cell Ci (1 ≤ Ci ≤ L), and can launch darts at any Bloons that are no more than Ri (0 ≤ Ri ≤ 1000) cells away - that is, Bloons in cells CiRi to Ci + Ri, inclusive. Every second, it will do Di (1 ≤ Di ≤ 109) HP worth of damage to any Bloons in this range.

M (1 ≤ M ≤ 1000) Bloons will attempt to float through your course, one after another. The i-th Bloon begins with Hi (1 ≤ Hi ≤ 109) HP, and will pop as soon as it has taken at least that much damage in total. Each Bloon starts in cell 1, and moves along the course at a speed of 1 cell per second. If a Bloon moves past cell L, it safely exits the course and can no longer be popped.

There are T (1 ≤ T ≤ 20) scenarios as described above. For each, you'd like to determine how far along the course each of the M Bloons will make it.


Line 1: 1 integer, T
For each scenario:
Line 1: 2 integers, L and N
Next N lines: 3 integers, Ci, Ri, and Di, for i = 1..N
Next line: 1 integer, M
Next M lines: 1 integer, Hi, for i = 1..M


For each scenario:
M lines: If the i-th Bloon will survive the course, the string "Bloon leakage" (without quotes) - otherwise, 1 integer, the furthest cell which the i-th Bloon will reach, for i = 1..M

Sample Input

10 3
3 3 1
4 0 4
10 2 2

Sample Output

Bloon leakage

Explanation of Sample

The following diagram illustrates which cells each tower can hit:

The first Bloon, having only 1 HP, will go down to the first tower in cell 1.
The second Bloon will manage to clear the course, surviving past cell 10 with 4 HP remaining.
The third Bloon will lose its final HP while at cell 5, having taken 5 damage from the first tower, and 4 from the second.
The final Bloon will survive past cell 6 with 1 HP remaining, but will then go down at cell 8 when it takes 2 damage from the third tower.

All Submissions
Best Solutions

Point Value: 10
Time Limit: 5.00s
Memory Limit: 64M
Added: Oct 02, 2012
Author: SourSpinach

Languages Allowed:

Comments (Search)

What am I doing wrong?

Can you give some examples of test cases that you've written and used to test your program?

Got it,
Apparently list[-1] get you the last element in list

Thank you