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Title User Message Date Posted
Re: ... jargon You are experiencing significant loss of precision. Edit: I was wrong. Your code was right, and the judge was wrong. I apologise. Jan 02, 2017 - 7:44:02 am UTC
... IMAGenius I'm not sure why my program doesn't work Dec 31, 2016 - 8:22:53 pm UTC
Re: Rounding for this question? ImbaCalvin The exact answer is actually 51.9029278687 31.8950997212 Jan 12, 2014 - 1:38:21 am UTC
Rounding for this question? Butane OK, so I tried all sorts of rounding methods, but I keep getting the wrong answer. In the sample input, my program rounds the speed of the stone to 31.93. How was the sample input rounded, because the... Jan 12, 2014 - 12:05:56 am UTC
Re: Re: HOW? HelloMelloC LOL. No need for physics here, I just BF'ed. Digital technology's so great (compared to analog) as you can just set an arbitrary precision depending on how precise the situation needs (with the equiva... Jan 27, 2011 - 3:36:59 pm UTC
Re: Re: HOW? ilovepi I will listen to your advice. TY. Jan 18, 2011 - 12:18:22 am UTC
Re: Re: HOW? SourSpinach I recommend simply not doing this question until you've taken Grade 11 Physics. Jan 17, 2011 - 4:04:04 am UTC
Re: Re: HOW? bbi5291 These equations describe uniformly accelerated linear motion, where Δt is elapsed time, Δd is displacement, v₁ is initial velocity, v₂ is final velocity, and a is acceleration. Jan 17, 2011 - 12:36:47 am UTC
Re: Re: HOW? ilovepi Well then could you tell me the meaning of the equations? It's so hard to understand when your only in grade 7. Jan 16, 2011 - 6:00:24 pm UTC
Re: HOW? bbi5291 It's not hard; it just requires a basic understanding of high school algebra and physics. The point value stands. (I even gave you the equations of kinematics you need to solve this!) Jan 15, 2011 - 10:31:08 pm UTC