### 2013 Canadian Computing Competition, Stage 1

## Problem J1: Next in line

You know a family with three children. Their ages form an arithmetic sequence: the difference in ages between the middle child and youngest child is the same as the difference in ages between the oldest child and the middle child. For example, their ages could be 5, 10 and 15, since both adjacent pairs have a difference of 5 years.

Given the ages of the youngest and middle children, what is the age of the oldest child?

### Input

The input consists of two integers, each on a separate line. The first line
is the age `Y` of the youngest child
(0 ≤ `Y` ≤ 50). The second line is the age
`M` of the middle child
(`Y` ≤ `M` ≤ 50).

### Output

The output will be the age of the oldest child.

### Sample Input 1

12 15

### Sample Output 1

18

### Sample Input 2

10 10

### Sample Output 2

10

All Submissions

Best Solutions

**Point Value:** 3

**Time Limit:** 2.00s

**Memory Limit:** 16M

**Added:** May 18, 2013

**Languages Allowed:**

C++03, PAS, C, HASK, ASM, RUBY, PYTH2, JAVA, PHP, SCM, CAML, PERL, C#, C++11, PYTH3

## Comments (Search)

jimpixon Jul 03, 2016 - 1:03:13 pm UTC Too Easyspencereiron Jul 04, 2016 - 12:58:11 am UTC Re: Too Easytry this one instead

http://wcipeg.com/problem/ccc13s2p6